Lakers Speculation Boils After Post From Brother Of Award-Winning Guard

The Los Angeles Lakers showed interest in several players this offseason, including Bojan Bogdanovic and Jordan Clarkson. The Utah Jazz were a reasonable trade partner for the Lakers as they still try to find a trade partner for Russell Westbrook. Utah is no longer an option for the purple and gold. What about Clarkson? Will Pelinka try to get Clarkson? The Lakers have been part of huge speculation and the brother of a talented guard sure added fuel to it.

Clarkson may leave his current team sooner than expected. He was a Laker back in the days and spent four years with the franchise. The Lakers traded him to the Cleveland Cavaliers and Clarkson became one of the best sixth men in the NBA. LA may try to get him again.

Lakers speculation revolves around the talented guard

Clarkson’s brother added fuel to the fire, too. His latest Instagram activity made people talk. Bear took a video of Jordan’s jersey on the wall. Should we even mention that the jersey was hung next to the jersey of LeBron James and Anthony Davis? What does this mean?

Jordan would be an excellent addition to the Lakers at this point. He may no longer be a good fit for the Jazz as they try to rebuild the team. The franchise got rid of most of its players. Who is the next to go?

Clarkson, 30, has plans for his future. He could work well for any contender. The Lakers are looking for players who can play alongside LeBron and AD and this makes Clarkson an excellent addition.

Getting Clarkson won’t be that easy though. The Lakers don’t have many tradeable assets. They have already traded for Patrick Beverley. Russ is the only asset they can offer right now. Got the point? Pelinka can trade Westbrook, but he would receive Malik Beasley, Mike Conley, and Clarkson. Do they really need those guards? Absolutely not.

Head coach Darvin Ham could use Carlson as a scorer from the bench. He doesn’t need any guards as they have Russ, Beverley, Austin Reaves, Kendrick Nunn, and Dennis Schroder.